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3n^2-0.75+3n^2-0.75=180
We move all terms to the left:
3n^2-0.75+3n^2-0.75-(180)=0
We add all the numbers together, and all the variables
6n^2-181.5=0
a = 6; b = 0; c = -181.5;
Δ = b2-4ac
Δ = 02-4·6·(-181.5)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*6}=\frac{-66}{12} =-5+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*6}=\frac{66}{12} =5+1/2 $
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